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5a^2-23a=-12
We move all terms to the left:
5a^2-23a-(-12)=0
We add all the numbers together, and all the variables
5a^2-23a+12=0
a = 5; b = -23; c = +12;
Δ = b2-4ac
Δ = -232-4·5·12
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-17}{2*5}=\frac{6}{10} =3/5 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+17}{2*5}=\frac{40}{10} =4 $
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